We do not have statistically significant evidence at a =0.05 to show that there is a difference in mean calcium intake in patients with normal bone density as compared to osteopenia and osterporosis. We do not reject H 0 because 1.395 < 3.68. For the participants with normal bone density: SSE requires computing the squared differences between each observation and its group mean. If we pool all N=18 observations, the overall mean is 817.8. In order to compute the sums of squares we must first compute the sample means for each group and the overall mean. To organize our computations we will complete the ANOVA table. The critical value is 3.68 and the decision rule is as follows: Reject H 0 if F > 3.68. In order to determine the critical value of F we need degrees of freedom, df 1=k-1 and df 2=N-k. The test statistic is the F statistic for ANOVA, F=MSB/MSE. Set up hypotheses and determine level of significance Is there a statistically significant difference in mean calcium intake in patients with normal bone density as compared to patients with osteopenia and osteoporosis? We will run the ANOVA using the five-step approach.

Each participant's daily calcium intake is measured based on reported food intake and supplements.

Adults 60 years of age with normal bone density, osteopenia and osteoporosis are selected at random from hospital records and invited to participate in the study. Unfortunately some of the supplements have side effects such as gastric distress, making them difficult for some patients to take on a regular basis.Р В РІР‚СњР В РІР‚С› study is designed to test whether there is a difference in mean daily calcium intake in adults with normal bone density, adults with osteopenia (a low bone density which may lead to osteoporosis) and adults with osteoporosis. While calcium is contained in some foods, most adults do not get enough calcium in their diets and take supplements. The National Osteoporosis Foundation recommends a daily calcium intake of 1000-1200 mg/day for adult men and women. Thus, the engineer should not use the model to make generalizations beyond the sample data.Calcium is an essential mineral that regulates the heart, is important for blood clotting and for building healthy bones. The imprecision may be due to the small size of the groups. The low predicted R 2 (24.32%) value indicates that the model generates imprecise predictions for new observations. The confidence intervals for the remaining pairs of means all include zero, which indicates that the differences are not significant. The engineer can use this estimate of the difference to determine whether the difference is practically significant. This range does not include zero, which indicates that the difference between these means is significant. The graph that includes the Tukey simultaneous confidence intervals show that the confidence interval for the difference between the means of Blend 2 and 4 is 3.114 to 15.886. The engineer uses the Tukey comparison results to formally test whether the difference between a pair of groups is statistically significant. The engineer knows that some of the group means are different. This result indicates that the hardness of the paint blends differs significantly. The p-value for the paint hardness ANOVA is less than 0.05.

One way anova examples in real life